L\u00f4 xi\u00ean l\u00e0 m\u1ed9t trong nh\u1eefng h\u00ecnh th\u1ee9c ch\u01a1i l\u00f4 \u0111\u1ec1 ph\u1ed5 bi\u1ebfn hi\u1ec7n nay. Lo\u1ea1i ch\u01a1i l\u00f4 n\u00e0y \u0111ang v\u00f4 c\u00f9ng \u0111\u01b0\u1ee3c \u01b0a chu\u1ed9ng. B\u1edfi c\u00e1ch ch\u01a1i t\u01b0\u01a1ng \u0111\u1ed1i \u0111\u01a1n gi\u1ea3n, ti\u1ec1n ch\u01a1i th\u1ea5p m\u00e0 t\u1ef7 l\u1ec7 \u0103n ph\u1ea3i g\u1ecdi l\u00e0 c\u1ef1c cao. N\u1ebfu b\u1ea1n bi\u1ebft c\u00e1ch \u0111\u00e1nh v\u00e0 \u00e1p d\u1ee5ng ph\u01b0\u01a1ng ph\u00e1p soi xi\u00ean kh\u00e9o l\u00e9o. Th\u00ec kh\u00f4ng c\u00f3 l\u00fd do g\u00ec l\u1ea1i kh\u00f4ng \u0103n ngay ti\u1ec1n th\u01b0\u1edfng. V\u1eady c\u00e1ch \u0111\u00e1nh th\u1ebf n\u00e0o l\u00e0 ch\u00ednh x\u00e1c? V\u00e0 ch\u01a1i l\u00f4 xi\u00ean \u0103n bao nhi\u00eau? \u0110\u1eebng ch\u1ea7n ch\u1eeb m\u00e0 h\u00e3y tham gia ch\u01a1i ngay, v\u1edbi c\u00e1ch \u0111\u00e1nh v\u00f4 c\u00f9ng \u0111\u1eb3ng c\u1ea5p sau \u0111\u00e2y.<\/em><\/p>\n C\u00f2n n\u1ebfu \u0111\u00e3 c\u00f3 b\u1ed9 xi\u00ean chu\u1ea9n cho m\u00ecnh r\u1ed3i.<\/p>\n \u0110\u1ec3 c\u00f3 th\u1ec3 v\u1eadn d\u1ee5ng linh ho\u1ea1t v\u00e0 kh\u00e9o l\u00e9o c\u00e1ch ch\u01a1i l\u00f4 xi\u00ean. Th\u00ec tr\u01b0\u1edbc ti\u00ean ta c\u1ea7n ph\u1ea3i n\u1eafm r\u00f5 nh\u1eefng \u0111\u1eb7c \u0111i\u1ec3m c\u01a1 b\u1ea3n c\u1ee7a lo\u1ea1i ch\u01a1i l\u00f4 \u0111\u1ec1 n\u00e0y. Ch\u1ec9 khi n\u1eafm r\u00f5 v\u00e0 hi\u1ec3u \u0111\u01b0\u1ee3c quy lu\u1eadt c\u1ee7a ch\u00fang. Th\u00ec \u201cb\u00e1ch chi\u1ebfn b\u00e1ch th\u1eafng\u201d l\u00e0 \u0111i\u1ec1u t\u1ea5t y\u1ebfu.<\/p>\n L\u00f4 xi\u00ean hay c\u00f2n \u0111\u01b0\u1ee3c g\u1ecdi l\u00e0 l\u00f4 xi\u00ean quay. L\u00f4 xi\u00ean l\u00e0 m\u1ed9t lo\u1ea1i h\u00ecnh th\u1ee9c c\u00e1 c\u01b0\u1ee3c k\u1ebft qu\u1ea3 x\u1ed5 s\u1ed1. \u1ede h\u00ecnh th\u1ee9c n\u00e0y ng\u01b0\u1eddi ch\u01a1i kh\u00f4ng \u0111\u00e1nh nh\u1eefng con l\u00f4 ri\u00eang l\u1ebb nh\u01b0 b\u00ecnh th\u01b0\u1eddng. M\u00e0 \u0111\u00e1nh c\u00f9ng m\u1ed9t l\u00fac 2, 3 ho\u1eb7c 4 con l\u00f4 kh\u00e1c nhau. N\u1ebfu k\u1ebft qu\u1ea3 x\u1ed5 s\u1ed1 ki\u1ebfn thi\u1ebft c\u00f3 s\u1ed1 cu\u1ed1i tr\u00f9ng v\u1edbi 2, 3 ho\u1eb7c 4 con l\u00f4 \u0111\u00f3 th\u00ec ng\u01b0\u1eddi ch\u01a1i s\u1ebd tr\u00fang th\u01b0\u1edfng. Ng\u01b0\u1ee3c l\u1ea1i ch\u1ec9 c\u1ea7n k\u1ebft qu\u1ea3 x\u1ed5 s\u1ed1 ki\u1ebfn thi\u1ebft kh\u00f4ng c\u00f3 1 con l\u00f4 b\u1ea5t k\u1ef3 trong xi\u00ean th\u00ec ng\u01b0\u1eddi ch\u01a1i s\u1ebd kh\u00f4ng tr\u00fang.<\/p>\n Ch\u00ednh v\u00ec c\u00f9ng m\u1ed9t l\u00fac \u0111\u00e1nh nhi\u1ec1u con l\u00f4 nh\u01b0 v\u1eady. N\u00ean ng\u01b0\u1eddi ta m\u1edbi n\u00f3i t\u1ef7 l\u1ec7 tr\u00fang th\u01b0\u1edfng c\u1ee7a h\u00ecnh th\u1ee9c ch\u01a1i l\u00f4 xi\u00ean l\u00e0 v\u00f4 c\u00f9ng cao.<\/p>\n L\u00f4 xi\u00ean hi\u1ec7n nay \u0111\u01b0\u1ee3c ch\u01a1i v\u1edbi nhi\u1ec1u lo\u1ea1i kh\u00e1c nhau. Tuy nhi\u00ean, ph\u1ed5 bi\u1ebfn nh\u1ea5t v\u1eabn l\u00e0 3 lo\u1ea1i sau \u0111\u00e2y.<\/p>\n L\u00e0 ng\u01b0\u1eddi ch\u01a1i \u0111\u01b0\u1ee3c ch\u1ecdn 2 s\u1ed1 l\u00f4 kh\u00e1c nhau. M\u1ed7i s\u1ed1 g\u1ed3m bao g\u1ed3m 1 ch\u1eef s\u1ed1 t\u1eeb 00 \u0111\u1ebfn 99. Sau \u0111\u00f3 k\u1ebft h\u1ee3p th\u00e0nh m\u1ed9t c\u1eb7p \u0111\u1ec3 \u0111\u00e1nh c\u01b0\u1ee3c<\/p>\n K\u1ebft qu\u1ea3 c\u1ee7a l\u00f4 xi\u00ean 2 \u0111\u01b0\u1ee3c t\u00ednh d\u1ef1a v\u00e0o hai ch\u1eef s\u1ed1 cu\u1ed1i c\u00f9ng c\u1ee7a t\u1ea5t c\u1ea3 c\u00e1c ph\u1ea7n th\u01b0\u1edfng c\u1ee7a gi\u1ea3i x\u1ed5 s\u1ed1 theo v\u00f9ng mi\u1ec1n c\u1ee7a b\u1ea1n. Hi\u1ec7n nay n\u01b0\u1edbc ta c\u00f3 27 l\u00f4 gi\u1ea3i c\u1ee7a \u0111\u00e0i H\u00e0 N\u1ed9i, 18 gi\u1ea3i c\u1ee7a \u0111\u00e0i Mi\u1ec1n Trung v\u00e0 Mi\u1ec1n Nam. B\u1ea1n x\u00e1c \u0111\u1ecbnh v\u00e0 t\u00ecm k\u1ebft qu\u1ea3 t\u00f9y theo v\u00f9ng mi\u1ec1n c\u1ee7a b\u1ea1n<\/p>\n N\u1ebfu s\u1ed1 l\u00f4 m\u00e0 b\u1ea1n l\u1ef1a ch\u1ecdn tr\u00f9ng v\u1edbi s\u1ed1 l\u00f4 trong k\u1ebft qu\u1ea3 c\u1ee7a gi\u1ea3i ki\u1ebfn thi\u1ebft th\u00ec c\u00f3 ngh\u0129a b\u1ea1n \u0111\u00e3 tr\u00fang.<\/p>\n V\u00ed d\u1ee5 cho c\u1eb7p s\u1ed1 l\u00f4 xi\u00ean 2: 53 \u2013 59 hay 03 \u2013 10<\/p>\n T\u01b0\u01a1ng t\u1ef1 nh\u01b0 l\u00f4 xi\u00ean 2. Nh\u01b0ng b\u1ea1n ch\u1ecdn 3 s\u1ed1 l\u00f4, m\u1ed7i s\u1ed1 bao g\u1ed3m c\u00f3 2 ch\u1eef s\u1ed1 t\u1eeb 00 \u0111\u1ebfn 99.<\/p>\n K\u1ebft qu\u1ea3 x\u00e1c \u0111\u1ecbnh c\u0169ng s\u1ebd \u0111\u01b0\u1ee3c d\u1ef1a v\u00e0o 2 ch\u1eef s\u1ed1 cu\u1ed1i c\u00f9ng c\u1ee7a gi\u1ea3i x\u1ed5 s\u1ed1 ki\u1ebfn thi\u1ebft. N\u1ebfu c\u1ea3 3 s\u1ed1 l\u00f4 c\u1ee7a b\u1ea1n tr\u00f9ng v\u1edbi k\u1ebft qu\u1ea3 x\u1ed5 s\u1ed1 th\u00ec b\u1ea1n \u0111\u01b0\u1ee3c t\u00ednh l\u00e0 \u0111\u00e3 tr\u00fang.<\/p>\n V\u00ed d\u1ee5 s\u1ed1 l\u00f4 xi\u00ean 3: 14 \u2013 85 \u2013 19 hay 03 \u2013 10 \u2013 69<\/p>\n C\u00e1ch ch\u01a1i l\u00f4 xi\u00ean 4 c\u0169ng t\u01b0\u01a1ng t\u1ef1 nh\u01b0 2 lo\u1ea1i l\u00f4 xi\u00ean tr\u00ean. Ng\u01b0\u1eddi ch\u01a1i ch\u1ecdn 4 con s\u1ed1 kh\u00e1c nhau, m\u1ed7i s\u1ed1 bao g\u1ed3m c\u00f3 2 ch\u1eef s\u1ed1 t\u1eeb 00 \u0111\u1ebfn 99.<\/p>\n N\u1ebfu c\u1ea3 4 con l\u00f4 \u0111\u00f3 tr\u00f9ng v\u1edbi s\u1ed1 cu\u1ed1i c\u1ee7a c\u1ee7a k\u1ebft qu\u1ea3 gi\u1ea3i x\u1ed5 s\u1ed1 th\u00ec b\u1ea1n \u0111\u00e3 tr\u00fang th\u01b0\u1edfng<\/p>\n V\u00ed d\u1ee5 s\u1ed1 l\u00f4 xi\u00ean quay 4: 52 \u2013 59 \u2013 90 \u2013 84, hay 03 \u2013 10 \u2013 69 \u2013 47<\/p>\n Ch\u1eafc h\u1eb3n b\u1ea1n \u0111ang th\u1eafc t\u1ef7 l\u1ec7 tr\u00fang l\u00f4 xi\u00ean quay l\u00e0 bao nhi\u00eau v\u00e0 \u0111\u01b0\u1ee3c x\u00e1c \u0111\u1ecbnh nh\u01b0 th\u1ebf n\u00e0o? C\u00e2u tr\u1ea3 l\u1eddi c\u1ee7a b\u1ea1n s\u1ebd \u0111\u01b0\u1ee3c gi\u1ea3i \u0111\u00e1p ngay sau \u0111\u00e2y<\/p>\n Nh\u00ecn ch\u00fang, theo \u0111\u00e1nh gi\u00e1 c\u1ee7a c\u00e1c chuy\u00ean gia v\u00e0 kinh nghi\u1ec7m c\u1ee7a nh\u1eefng tay ch\u01a1i chuy\u00ean nghi\u1ec7p. M\u1ed7i 1 con l\u00f4 s\u1ebd c\u00f3 t\u1ef7 l\u1ec7 tr\u00fang l\u00e0 27% v\u1edbi l\u00f4 mi\u1ec1n b\u1eafc, 18% v\u1edbi l\u00f4 mi\u1ec1n nam v\u00e0 mi\u1ec1n trung.<\/p>\n C\u1ee5 th\u1ec3 ta c\u00f3 th\u1ec3 t\u00ednh t\u1ef7 l\u1ec7 x\u00e1c xu\u1ea5t tr\u00f9ng th\u01b0\u1edfng theo t\u1eebng lo\u1ea1i l\u00f4 xi\u00ean s\u1ebd l\u00e0 nh\u01b0 sau:<\/p>\n + L\u00f4 xi\u00ean 2 s\u1ebd nh\u00e2n 2 l\u1ea7n: Mi\u1ec1n b\u1eafc: 27% x 27% = 0,0729, t\u1ee9c x\u00e1c xu\u1ea5t tr\u00fang l\u00e0 7,2 %. Mi\u1ec1n nam v\u00e0 mi\u1ec1n trung: 18% x 18% = 0,0324, t\u1ee9c x\u00e1c xu\u1ea5t tr\u00fang s\u1ebd l\u00e0 3,2%<\/p>\n + L\u00f4 xi\u00ean 3 ta s\u1ebd nh\u00e2n 3 l\u1ea7n: Mi\u1ec1n b\u1eafc: 27% x 27% x 27% = 0,01968, t\u1ee9c x\u00e1c xu\u1ea5t tr\u00fang s\u1ebd l\u00e0 1,9%. Mi\u1ec1n trung v\u00e0 mi\u1ec1n nam: 18% x 18% x 18%= 0,00583, t\u1ee9c x\u00e1c xu\u1ea5t tr\u00fang l\u00e0 0,58%<\/p>\n + L\u00f4 xi\u00ean 4 s\u1ebd nh\u00e2n 4 l\u1ea7n: Mi\u1ec1n b\u1eafc: 27% x 27% x 27% x 27% = 0,00531, t\u1ee9c x\u00e1c xu\u1ea5t tr\u00fang l\u00e0 0,5%. Mi\u1ec1n trung v\u00e0 mi\u1ec1n nam: 18% x 18% x 18% x 18% = 0,00104, t\u1ee9c x\u00e1c xu\u1ea5t tr\u00fang s\u1ebd l\u00e0 0,1<\/p>\n Ch\u1ec9 v\u1edbi v\u00e0i v\u00ed d\u1ee5 \u0111\u01a1n gi\u1ea3n nh\u01b0 tr\u00ean, ch\u1eafc ch\u1eafn b\u1ea1n \u0111\u00e3 c\u00f3 th\u1ec3 d\u1ec5 d\u00e0ng x\u00e1c \u0111\u1ecbnh \u0111\u01b0\u1ee3c cho m\u00ecnh t\u1ef7 l\u1ec7 tr\u00fang l\u00f4 xi\u00ean quy cho m\u00ecnh r\u1ed3i. Ch\u00ednh v\u00ec v\u1eady, c\u00f2n ch\u1ea7n ch\u1eeb g\u00ec m\u00e0 kh\u00f4ng tham gia ch\u01a1i ngay.<\/p>\n Sau khi \u0111\u00e3 hi\u1ec3u \u0111\u01b0\u1ee3c c\u01a1 b\u1ea3n v\u1ec1 h\u00ecnh th\u1ee9c ch\u01a1i l\u00f4 xi\u00ean quay n\u00e0y, ch\u00fang ta c\u00f3 th\u1ec3 \u0111\u00fac k\u1ebft l\u1ea1i c\u00e1ch ch\u01a1i l\u00f4 xi\u00ean v\u00f4 c\u00f9ng \u0111\u01a1n gi\u1ea3n nh\u01b0 sau:<\/p>\n + B\u01b0\u1edbc 1: Ch\u1ecdn 2 \u2013 3 \u2013 4 con l\u00f4 kh\u00f4ng tr\u00f9ng nhau theo \u0111\u00e1nh gi\u00e1 c\u1ee7a b\u1ea1n l\u00e0 c\u00f3 kh\u1ea3 n\u0103ng v\u1ec1 nh\u1ea5t. Gh\u00e9p ch\u00fang \u0111\u1ec3 t\u1ea1o ra 1 ho\u1eb7c 1 nh\u00f3m c\u00e1c c\u1ea7u xi\u00ean l\u1ea7n l\u01b0\u1ee3t l\u00e0 xi\u00ean 2, xi\u00ean 3 v\u00e0 xi\u00ean 4 (l\u01b0u \u00fd, v\u1edbi 3 ho\u1eb7c 4 con c\u00f3 th\u1ec3 t\u1ea1o ra nhi\u1ec1u xi\u00ean 2 ho\u1eb7c 3)<\/p>\n + B\u01b0\u1edbc 2: \u0110\u01b0a ra s\u1ed1 ti\u1ec1n (s\u1ed1 \u0111i\u1ec3m) m\u00e0 b\u1ea1n mu\u1ed1n \u0111\u00e1nh<\/p>\n + B\u01b0\u1edbc 3: Ch\u1edd gi\u1edd so k\u1ebft qu\u1ea3 c\u1ee7a \u0111\u00e0i b\u1ea1n ch\u01a1i<\/p>\n + B\u01b0\u1edbc 4: Nh\u1eadn ti\u1ec1n th\u1eafng n\u1ebfu tr\u00fang \u0111\u1ee7 c\u00e1c con l\u00f4 trong c\u1ea7u<\/p>\n V\u00f4 c\u00f9ng \u0111\u01a1n gi\u1ea3n. T\u1ef7 l\u1ec7 tr\u00fang l\u1ea1i cao. Ng\u1ea1i g\u00ec kh\u00f4ng th\u1eed<\/p>\n V\u1eady ch\u01a1i l\u00f4 xi\u00ean \u0103n bao nhi\u00eau? Sau \u0111\u00e2y s\u1ebd l\u00e0 s\u1ed1 ti\u1ec1n b\u1ea1n nh\u1eadn \u0111\u01b0\u1ee3c n\u1ebfu tr\u00fang theo t\u1eebng lo\u1ea1i l\u00f4 xi\u00ean quay.<\/p>\n L\u00f4 xi\u00ean 2 mi\u1ec1n b\u1eafc:<\/strong><\/p>\n + T\u1ef7 l\u1ec7 \u0103n l\u00f4 xi\u00ean mi\u1ec1n b\u1eafc c\u1ee7a c\u00f4ng ty x\u1ed5 s\u1ed1 ki\u1ebfn thi\u1ebft l\u00e0 1 \u0103n 10. T\u1ee9c l\u00e0 n\u1ebfu b\u1ea1n c\u01b0\u1ee3c 10.000 \u0111\u1ed3ng cho c\u1eb7p xi\u00ean \u0111\u00f4i. Th\u00ec khi tr\u00fang b\u1ea1n s\u1ebd nh\u1eadn 100.000 \u0111\u1ed3ng. C\u00f2n v\u1edbi trang c\u00e1 \u0111\u1ed9 uy t\u00edn<\/em> v\u1ec1 l\u00f4 \u0111\u1ec1 th\u00ec t\u1ef7 l\u1ec7 c\u00f2n cao h\u01a1n<\/p>\n + T\u1ef7 l\u1ec7 \u0103n l\u00f4 xi\u00ean mi\u1ec1n b\u1eafc theo nh\u00e0 c\u00e1i th\u00ec t\u00f9y thu\u1ed9c v\u00e0o quy \u0111\u1ecbnh c\u1ee7a t\u1eebng n\u01a1i. Th\u00f4ng th\u01b0\u1eddng t\u1ef7 l\u1ec7 s\u1ebd l\u00e0 1 \u0103n 17, quy \u0111\u1ecbnh m\u1ee9c \u0111\u1eb7t c\u01b0\u1ee3c th\u01b0\u1eddng cao h\u01a1n so v\u1edbi \u0111\u00e1nh l\u00f4 b\u1ea1ch th\u1ee7 th\u00f4ng th\u01b0\u1eddng.<\/p>\n T\u1ef7 l\u1ec7 1 \u0103n bao nhi\u00eau?<\/span><\/p>\n L\u00f4 xi\u00ean 2 mi\u1ec1n trung v\u00e0 mi\u1ec1n nam:<\/strong><\/p>\n + T\u1ef7 l\u1ec7 \u0103n l\u00f4 xi\u00ean mi\u1ec1n nam hi\u1ec7n nay theo nh\u00e0 c\u00e1i th\u00ec 1 \u0111i\u1ec3m l\u00f4 \u0111\u01b0\u1ee3c t\u00ednh l\u00e0 29.000 vn\u0111. 1 \u0111i\u1ec3m l\u00f4 tr\u00fang s\u1ebd \u0103n \u0111\u01b0\u1ee3c 650.000 \u0111\u1ed3ng, v\u00e0 c\u0169ng t\u00f9y theo nh\u00e0 c\u00e1i m\u00e0 con s\u1ed1 n\u00e0y s\u1ebd thay \u0111\u1ed5i.<\/p>\n + T\u1ef7 l\u1ec7 \u0103n l\u00f4 xi\u00ean mi\u1ec1n trung hi\u1ec7n nay theo nh\u00e0 c\u00e1i th\u00ec 1 \u0111i\u1ec3m l\u00f4 \u0103n \u0111\u01b0\u1ee3c 30 l\u1ea7n s\u1ed1 ti\u1ec1n b\u1ecf ra, v\u00e0 c\u0169ng t\u00f9y theo nh\u00e0 c\u00e1i m\u00e0 con s\u1ed1 n\u00e0y s\u1ebd thay \u0111\u1ed5i.<\/p>\n L\u00f4 xi\u00ean 3 mi\u1ec1n b\u1eafc:<\/strong><\/p>\n + T\u1ef7 l\u1ec7 \u0103n l\u00f4 xi\u00ean 3 mi\u1ec1n b\u1eafc c\u1ee7a c\u00f4ng ty x\u1ed5 s\u1ed1 ki\u1ebfn thi\u1ebft l\u00e0 1 \u0103n 40. V\u00ed d\u1ee5 n\u1ebfu b\u1ea1n c\u01b0\u1ee3c 10.000 \u0111\u1ed3ng th\u00ec khi tr\u00fang, b\u1ea1n s\u1ebd nh\u1eadn v\u1ec1 400.000 \u0111\u1ed3ng.<\/p>\n + T\u1ef7 l\u1ec7 \u0103n l\u00f4 xi\u00ean 3 mi\u1ec1n b\u1eafc theo nh\u00e0 c\u00e1i th\u01b0\u1eddng c\u00f3 t\u1ef7 l\u1ec7 s\u1ebd l\u00e0 1 \u0103n 76. M\u1ed9t s\u1ed1 nh\u00e0 c\u00e1i th\u00ec m\u1ee9c n\u00e0y c\u00f2n cao h\u01a1n n\u1eefa, nh\u1ea5t l\u00e0 v\u1edbi nh\u1eefng nh\u00e0 c\u00e1i online c\u00e1 c\u01b0\u1ee3c, con s\u1ed1 t\u1ef7 l\u1ec7 nay c\u00f3 th\u1ec3 l\u00ean t\u1edbi 5900 l\u1ea7n.<\/p>\n L\u00f4 xi\u00ean 3 mi\u1ec1n nam v\u00e0 mi\u1ec1n trung:<\/strong><\/p>\n + T\u1ef7 l\u1ec7 \u0103n l\u00f4 xi\u00ean 3 mi\u1ec1n nam hi\u1ec7n nay theo nh\u00e0 c\u00e1i th\u00ec 1 \u0111i\u1ec3m l\u00f4 \u0111\u01b0\u1ee3c t\u00ednh l\u00e0 43.000 vn\u0111, 1 \u0111i\u1ec3m l\u00f4 tr\u00fang s\u1ebd \u0103n \u0111\u01b0\u1ee3c 3.500.000 \u0111\u1ed3ng. C\u0169ng t\u00f9y theo nh\u00e0 c\u00e1i m\u00e0 con s\u1ed1 n\u00e0y s\u1ebd thay \u0111\u1ed5i.<\/p>\n + T\u1ef7 l\u1ec7 \u0103n l\u00f4 xi\u00ean 3 mi\u1ec1n trung th\u00ec s\u1ebd ph\u1ee5 thu\u1ed9c v\u00e0o nh\u00e0 c\u00e1i. Tuy nhi\u00ean, th\u01b0\u1eddng th\u00ec t\u1ef7 l\u1ec7 \u0103n s\u1ebd cao h\u01a1n so v\u1edbi xi\u00ean 3.<\/p>\n L\u00f4 xi\u00ean 4 mi\u1ec1n b\u1eafc:<\/strong><\/p>\n + T\u1ef7 l\u1ec7 \u0103n c\u1ee7a l\u00f4 xi\u00ean quay 4 l\u00e0 1\/100. T\u1ee9c l\u00e0 khi c\u01b0\u1ee3c 10.000 \u0111\u1ed3ng, n\u1ebfu tr\u00fang b\u1ea1n s\u1ebd \u0103n 1.000.000 \u0111\u1ed3ng.<\/p>\n + T\u1ea1i c\u00e1c nh\u00e0 c\u00e1i th\u00ec s\u1ed1 ti\u1ec1n \u0103n c\u00f3 th\u1ec3 g\u1ea5p l\u00ean r\u1ea5t nhi\u1ec1u. Th\u1eadm ch\u00ed g\u1ea5p 320 l\u1ea7n s\u1ed1 ti\u1ec1n ban \u0111\u1ea7u b\u1ea1n b\u1ecf ra. T\u1ee9c l\u00e0 1 \u0103n 320.<\/p>\n L\u00f4 xi\u00ean 4 mi\u1ec1n trung v\u00e0 mi\u1ec1n nam<\/strong>: H\u00ecnh th\u1ee9c ch\u01a1i l\u00f4 xi\u00ean n\u00e0y theo c\u00e1c nh\u00e0 c\u00e1i hi\u1ec7n nay th\u01b0\u1eddng c\u00f3 t\u1ef7 l\u1ec7 \u0103n r\u1ea5t cao. C\u00f3 th\u1ec3 l\u00ean t\u1edbi 1 \u0103n 720<\/p>\n L\u00f4 xi\u00ean 2 \u2013 xi\u00ean 3 hay xi\u00ean 4 \u0111\u1ec1u l\u00e0 t\u1eeb nh\u1eefng con l\u00f4 l\u1ebb gh\u00e9p th\u00e0nh. Ch\u00fang c\u00f3 \u0111i\u1ec1u ki\u1ec7n c\u1ea7n l\u00e0 ph\u1ea3i v\u1ec1 \u0111\u1ee7 t\u1ea5t c\u1ea3 nh\u1eefng con trong xi\u00ean th\u00ec b\u1ea1n m\u1edbi tr\u00fang. Do \u0111\u00f3, b\u1ea1n c\u00f3 th\u1ec3 l\u1ef1a ch\u1ecdn nh\u1eefng ph\u01b0\u01a1ng ph\u00e1p cho ra nhi\u1ec1u con l\u00f4 b\u1ea1ch th\u1ee7. Ho\u1eb7c soi d\u00e0n l\u00f4 \u0111\u1ec3 x\u1ebfp xi\u00ean. C\u0169ng c\u00f3 th\u1ec3 d\u1ef1a tr\u00ean c\u1edd b\u1ea1c nh\u1edb \u0111\u1ec3 l\u1ea5y ra nh\u1eefng con l\u00f4 t\u1ed1t nh\u1ea5t. C\u00f3 th\u1ec3 tham kh\u1ea3o m\u1ed9t c\u00e1ch sau \u0111\u00e2y<\/p>\n Theo c\u00e1ch nu\u00f4i l\u00f4 n\u00e0y th\u00ec ng\u01b0\u1eddi ch\u01a1i n\u00ean ch\u1ecdn c\u1eb7p l\u00f4 \u1edf nh\u1eefng c\u1ea7u \u0111ang \u1edf max gan l\u00ec \u0111\u1ec3 nu\u00f4i s\u1ebd c\u00f3 t\u00ednh kh\u1ea3 quan h\u01a1n. Th\u01b0\u1eddng nh\u1eefng ch\u1ed7 an to\u00e0n th\u00ec b\u1ea1n n\u00ean \u0111\u1ec3 c\u1ea7u \u0111\u00f3 v\u01b0\u1ee3t max gan tr\u01b0\u1edbc \u0111\u00f3 1, 2, 3 ng\u00e0y. R\u1ed3i b\u1eaft \u0111\u1ea7u v\u00e0o ti\u1ec1n nu\u00f4i l\u00f4 khung 3 ng\u00e0y.<\/p>\n Ngo\u00e0i ra th\u00ec b\u1ea1n c\u0169ng c\u00f3 th\u1ec3 l\u1ef1a ch\u1ecdn nh\u1eefng c\u1ea7u c\u00f3 t\u1ea7n xu\u1ea5t xu\u1ea5t hi\u1ec7n \u0111\u1ec1u nh\u1ea5t kho\u1ea3ng 2, 3, 4 ng\u00e0y r\u1ed3i ch\u1edd tr\u01b0\u1edbc max 1 ng\u00e0y r\u1ed3i m\u1edbi v\u00e0o ti\u00ean nu\u00f4i khung 3 ng\u00e0y.<\/p>\n N\u1ebfu nu\u00f4i l\u00f4 t\u00f4 b\u1ea1ch th\u1ee7 th\u00ec ng\u01b0\u1eddi ch\u01a1i n\u00ean ch\u1ecdn khung 5 ng\u00e0y cho an to\u00e0n. \u0110\u1ed3ng th\u1eddi c\u00e1ch v\u00e0o ti\u1ec1n t\u01b0\u01a1ng t\u1ef1 gi\u1ed1ng nh\u01b0 nu\u00f4i l\u00f4 t\u00f4 c\u1eb7p. C\u1ea7n ch\u1ecdn nh\u1eefng c\u1ea7u l\u00f4 \u0111ang v\u01b0\u1ee3t max gan t\u1ea7m 0, 1, 2 ng\u00e0y th\u00ec b\u1ea1n b\u1eaft \u0111\u1ea7u v\u00e0o ti\u1ec1n nu\u00f4i khung trong 5 ng\u00e0y.<\/p>\n B\u1ea1n c\u1ea7n d\u1ef1a v\u00e0o hi\u1ec7n t\u01b0\u1ee3ng \u0111\u1eb7c bi\u1ec7t \u0111\u00f3 l\u00e0 c\u00f3 m\u1ed9t s\u1ed1 con l\u00f4 b\u1ecb c\u1ea5m d\u00e0i h\u1ea1n. N\u1ebfu nh\u01b0 v\u1eady x\u00e9t theo quy lu\u1eadt b\u00f9 tr\u1eeb th\u00ec ch\u1eafc ch\u1eafn s\u1ebd c\u00f3 nh\u1eefng con l\u00f4 ra \u0111\u1ec1u, c\u00f3 ngh\u0129a l\u00e0 c\u00f3 nh\u1eefng con hay ra ho\u1eb7c th\u01b0\u1eddng ra \u0111\u1ec1u \u0111\u1eb7n \u0111\u1ec3 l\u1ea5p v\u00e0o kho\u1ea3ng tr\u1ed1ng do c\u00e1c con l\u00f4 b\u1ecb c\u1ea5m b\u1ecf l\u1ea1i.<\/p>\n C\u00e1ch soi c\u1ea7u l\u00f4 theo t\u1ea7n xu\u1ea5t<\/strong> \u0111\u00f2i h\u1ecfi b\u1ea1n ph\u1ea3i c\u00f3 s\u1ef1 theo d\u00f5i k\u1ebft qu\u1ea3 c\u1ee7a nh\u1eefng con l\u00f4 tr\u01b0\u1edbc \u0111\u00f3. \u0110\u1ec3 soi c\u1ea7u v\u00e0 \u0111\u01b0a ra ph\u00e1n \u0111o\u00e1n nh\u1eefng con l\u00f4 c\u00f3 kh\u1ea3 n\u0103ng v\u1ec1 cao nh\u1ea5t cho m\u00ecnh<\/p>\n Ngo\u00e0i ra, hi\u1ec7n nay c\u00f2n c\u00f3 m\u1ed9t s\u1ed1 ph\u01b0\u01a1ng ph\u00e1p soi c\u1ea7u l\u00f4 \u0111\u1ec1 v\u00f4 c\u00f9ng hay v\u00e0 ch\u00ednh x\u00e1c. V\u00ed d\u1ee5 nh\u01b0 soi c\u1ea7u d\u1ef1a v\u00e0o s\u1ed1 \u0111\u1ea7u c\u00e2m, \u0111u\u00f4i c\u00e2m. Hay d\u1ef1a soi c\u1ea7u theo k\u1ebft qu\u1ea3 x\u1ed5 s\u1ed1 c\u00f3 tr\u01b0\u1edbc \u0111\u00f3,\u2026 C\u00e1c ph\u01b0\u01a1ng ph\u00e1p soi c\u1ea7u l\u00f4 \u0111\u1ec1 s\u1ebd \u0111em l\u1ea1i cho ng\u01b0\u1eddi ch\u01a1i nh\u1eefng k\u1ebft qu\u1ea3 c\u00f3 quy lu\u1eadt. Gi\u00fap t\u1ef7 l\u1ec7 tr\u00fang cao v\u00e0 v\u00f4 c\u00f9ng ch\u00ednh x\u00e1c. Ch\u00ednh v\u00ec v\u1eady, \u0111\u1eebng ng\u1ea1i t\u00ecm hi\u1ec3u v\u1ec1 c\u00e1c c\u00e1ch soi c\u1ea7u l\u00f4 \u0111\u1ec1<\/strong>. B\u1edfi ch\u00fang c\u00f3 th\u1ec3 s\u1ebd \u0111em l\u1ea1i cho b\u1ea1n s\u1ed1 ti\u1ec1n th\u01b0\u1edfng kh\u00f4ng h\u1ec1 nh\u1ecf.<\/p>\n<\/div>\n<\/article>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n <\/main><\/p>\nL\u00f4 xi\u00ean l\u00e0 g\u00ec? C\u00f3 m\u1ea5y lo\u1ea1i l\u00f4 xi\u00ean?<\/strong><\/span><\/h2>\n
1\/ L\u00f4 xi\u00ean l\u00e0 g\u00ec?<\/span><\/strong><\/h3>\n
2\/ C\u00f3 m\u1ea5y lo\u1ea1i l\u00f4 xi\u00ean?<\/strong><\/span><\/h3>\n
+ L\u00f4 xi\u00ean 2<\/strong><\/h4>\n
+ L\u00f4 xi\u00ean 3<\/strong><\/h4>\n
+ L\u00f4 xi\u00ean 4<\/strong><\/h4>\n
3\/ T\u1ef7 l\u1ec7 tr\u00fang l\u00f4 xi\u00ean ra sao?<\/strong><\/span><\/h3>\n
4\/ H\u01b0\u1edbng d\u1eabn \u0111\u00e1nh l\u00f4 xi\u00ean<\/strong><\/span><\/h3>\n
L\u00f4 xi\u00ean \u0103n bao nhi\u00eau?<\/strong><\/span><\/h2>\n
1\/ L\u00f4 xi\u00ean 2 10k \u0103n bao nhi\u00eau?<\/span><\/strong><\/h3>\n
2\/ L\u00f4 xi\u00ean quay 3 \u0103n bao nhi\u00eau?<\/strong><\/span><\/h3>\n
3\/ L\u00f4 xi\u00ean quay 4 \u0103n bao nhi\u00eau?<\/strong><\/span><\/h3>\n
M\u1ed9t s\u1ed1 ph\u01b0\u01a1ng ph\u00e1p soi c\u1ea7u l\u00f4 xi\u00ean<\/strong><\/span><\/h2>\n
1\/ Soi c\u1ea7u l\u00f4 theo t\u1ea7n su\u1ea5t<\/strong><\/span><\/h3>\n
2\/ D\u1ef1a tr\u00ean nh\u1eefng ph\u01b0\u01a1ng ph\u00e1p soi c\u1ea7u l\u00f4 \u0111\u1ec1<\/strong><\/span><\/h3>\n
c\u1ea7u si\u00eau \u0111\u1eb9p uy t\u00edn mi\u1ec1n b\u1eafc v\u00edp<\/span><\/strong><\/h4>\n